What is the total resistance of three 4.5 kΩ resistors and one 1.5 kΩ resistor connected in parallel?

What is the total resistance of three 4.5 kΩ resistors and one 1.5 kΩ resistor connected in parallel?

• A. 4.5 kΩ
• B. 750 ohms
• C. 6 kΩ
• D. 3.0 kΩ

Answer: (B)

To find the total resistance of resistors connected in parallel, you can use the formula: 1/R_total = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn In this case, you have three resistors of 4.5 kΩ each and one resistor of 1.5 kΩ. First, you convert the resistance values into ohms for easier calculations: - 4.5 kΩ = 4500 ohms - 1.5 kΩ = 1500 ohms Now, substituting the values into the formula, we get: 1/R_total = 1/4500 + 1/4500 + 1/4500 + 1/1500. Calculating each term: 1/R_total = 1/4500 + 1/4500 + 1/4500 = 3/4500 = 1/1500. Now add the fourth resistor: 1/R_total = 1/1500 + 1/1500 = 2/1500 = 1/750. This gives the reciprocal relationship: R_total = 750 ohms, which is equivalent to 0.750 k

To find the total resistance of resistors connected in parallel, you can use the formula:

1/R_total = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn

In this case, you have three resistors of 4.5 kΩ each and one resistor of 1.5 kΩ. First, you convert the resistance values into ohms for easier calculations:

• 4.5 kΩ = 4500 ohms

• 1.5 kΩ = 1500 ohms

Now, substituting the values into the formula, we get:

1/R_total = 1/4500 + 1/4500 + 1/4500 + 1/1500.

Calculating each term:

1/R_total = 1/4500 + 1/4500 + 1/4500 = 3/4500 = 1/1500.

Now add the fourth resistor:

1/R_total = 1/1500 + 1/1500 = 2/1500 = 1/750.

This gives the reciprocal relationship:

R_total = 750 ohms, which is equivalent to 0.750 k