What is the total current with 70 volts applied to two 30 kΩ resistors in series connected to three 30 kΩ resistors in parallel?

What is the total current with 70 volts applied to two 30 kΩ resistors in series connected to three 30 kΩ resistors in parallel?

• A. 0.5 mA
• B. 1 mA
• C. 2 mA
• D. 1.5 mA

Answer: (B)

To determine the total current flowing through the circuit with 70 volts applied to the resistors, we first need to calculate the equivalent resistance of the configuration consisting of two 30 kΩ resistors in series connected to three 30 kΩ resistors in parallel. For the two 30 kΩ resistors in series, the total resistance is the sum of their resistances: Total resistance in series = 30 kΩ + 30 kΩ = 60 kΩ. Next, we calculate the equivalent resistance of the three 30 kΩ resistors in parallel. The formula for the total resistance \(R_t\) of resistors in parallel is given by: \[ \frac{1}{R_t} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \] Substituting the values: \[ \frac{1}{R_t} = \frac{1}{30 kΩ} + \frac{1}{30 kΩ} + \frac{1}{30 kΩ} = \frac{3}{30 kΩ} = \frac{1}{10 kΩ} \] Thus, the total resistance

To determine the total current flowing through the circuit with 70 volts applied to the resistors, we first need to calculate the equivalent resistance of the configuration consisting of two 30 kΩ resistors in series connected to three 30 kΩ resistors in parallel.

For the two 30 kΩ resistors in series, the total resistance is the sum of their resistances:

Total resistance in series = 30 kΩ + 30 kΩ = 60 kΩ.

Next, we calculate the equivalent resistance of the three 30 kΩ resistors in parallel. The formula for the total resistance (R_t) of resistors in parallel is given by:

[

\frac{1}{R_t} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}

]

Substituting the values:

[

\frac{1}{R_t} = \frac{1}{30 kΩ} + \frac{1}{30 kΩ} + \frac{1}{30 kΩ} = \frac{3}{30 kΩ} = \frac{1}{10 kΩ}

]

Thus, the total resistance