If the voltage in a circuit is doubled and resistance remains constant, what happens to the current?

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Multiple Choice

If the voltage in a circuit is doubled and resistance remains constant, what happens to the current?

Explanation:
When the voltage in a circuit is doubled while keeping resistance constant, the current also doubles. This relationship is described by Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R), or mathematically expressed as I = V/R. If we increase the voltage to twice its original value (2V) and maintain the same resistance, the new current would be calculated as I = (2V)/R. This is clearly double the original current (I = V/R), thus confirming that the current increases in direct proportion to the voltage when resistance remains unchanged. Understanding this principle is important in electronics, as it illustrates how voltage changes directly affect current flow in a circuit, a crucial factor when designing and troubleshooting electrical systems.

When the voltage in a circuit is doubled while keeping resistance constant, the current also doubles. This relationship is described by Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R), or mathematically expressed as I = V/R.

If we increase the voltage to twice its original value (2V) and maintain the same resistance, the new current would be calculated as I = (2V)/R. This is clearly double the original current (I = V/R), thus confirming that the current increases in direct proportion to the voltage when resistance remains unchanged.

Understanding this principle is important in electronics, as it illustrates how voltage changes directly affect current flow in a circuit, a crucial factor when designing and troubleshooting electrical systems.

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